Two simple pendulums are in two different places. the length of the second pendulum is 0.4 times the length of the first pendulum, and the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum. determine the comparison of the frequency of the first pendulum to the second pendulum. a) 2/3. b) 3/2 (5 marks) c) 4/9. d) 9/4

Explanation:

The frequency of a simple pendulum is given by:

where

g is the acceleration of gravity

L is the length of the pendulum

Calling the length of the first pendulum and the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

The length of the second pendulum is 0.4 times the length of the first pendulum, so

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

So the frequency of the second pendulum is

Therefore the ratio between the two frequencies is

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..