Consider a car that is initially traveling along a straight stretch of highway at 15 m/s. at t=0 the car begins to accelerate at 2.0 m/s2 in order to pass a truck. the final velocity is vx=25m/s. calculate how far the car travels during its 5.0 s of acceleration.

The car travels 100 meter during its 5.0 s of acceleration

Explanation:

We have the equation of motion v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration ans s is the displacement.

v = 25 m/s

a = 2 m/s²

u = 15 m/s

Substituting

      25²=15²+2 x 2 x s

       s = 100 m

The car travels 100 meter during its 5.0 s of acceleration

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2