Nelectric motor rotating a workshop grinding wheel at a rate of 94 rev/min is switched off. assume constant negative angular acceleration of magnitude 1.70 rad/s. (a) how long does it take for the grinding wheel to stop? (b) through how many radians has the wheel turned during the interval found in (a)? rad

a) It takes 5.79 seconds for the grinding wheel to stop.

b) In an interval of 5.79 seconds it rotates 28.48 rad.

Explanation:

a) We have equation of motion v = u + at

  Here v = 0 rad/s, a = -1.70 rad/s², u = 94 rev/min = 9.84 rad/s

  Substituting

         0 = 9.84 - 1.70 x t

          t = 5.79 seconds.

It takes 5.79 seconds for the grinding wheel to stop.

b) We have equation of motion v² = u² + 2as

      v = 0 rad/s, a = -1.70 rad/s², u = 9.84 rad/s

  Substituting

         0² = 9.84² - 2 x 1.70 x s

          s = 28.48 rad

 So in an interval of 5.79 seconds it rotates 28.48 rad.

to be honest as much as i would love to answer this. i feel as if something's missing. just saying.

i don't know that i agree with that but what's the question ?