Runner a is initially 8.0 mi west of a flagpole and is running with a constant velocity of 7.0 mi/h due east. runner b is initially 7.0 mi east of the flagpole and is running with a constant velocity of 7.0 mi/h due west. how far are the runners from the flagpole when they meet?

The answer is b hope this

Ray 2 should cross through the focal point on the right side of the lens

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.