Electric field of ring of charge a ring shaped charge has a radius of 0.250 meters and bears a total charge of +5.00 c what is the magnitude of the electric field along the axis of symmetry of the ring a distance of 0.500 meters from the center of the ring? ? a. 1.29 × 105 n/c 0 b. 1.67 × 105 n/c o c. 2.59 x 105 n/c ? d. 3.95 × 105 n/c

6.44 × 10^10 N/C

Explanation:

Electric field due to the ring on its axis is given by

E = K q r / (r^2 + x^2)^3/2

Where r be the radius of ring and x be the distance of point from the centre of ring and q be the charge on ring.

r = 0.25 m, x = 0.5 m, q = 5 C

K = 9 × 10^9 Nm^2/C^2

E = 9 × 10^9 × 5 × 0.25 / (0.0625 + 0.25)^3/2

E = 6.44 × 10^10 N/C

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min