The earth is 81.25 times as massive as the moon and the radius of the earth is 3.668 times the radius of the moon. if a simple pendulum has a frequency of 2 hz on earth, what will be its frequency on the moon? a) 0.407 hz b) 0.814 hz c) 1.34 hz d) 1.22 hz e) 1.63 ha

option (b)

Explanation:

Mass of moon = m

Mass of earth = 81.25 x mass of moon = 81.25 m

Radius of moon = r

radius of earth = 3.668 x radius of moon  = 3.668 r

Frequency on earth = 2 Hz

Let the frequency on moon is f.

The formula for the frequency is given by

The value of acceleration due to gravity on earth is g.

ge = G Me / Re^2

ge = G x 81.25 m / (3.668 r)^2

ge = 6.039 x G m / r^2 = 6.039 x gm

ge / gm = 6.039

Now use the formula for frequency

fm = 0.814 Hz

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explanation: