A2,000-kg car moving east at 10.0 m/s collides with a 3,000-kg car moving north. the cars stick together and move as a unit after the collision, at an angle of 48.0° north of east and at a speed of 5.98 m/s. find the speed of the 3,000-kg car before the collision.

Speed of the 3,000-kg car before the collision = 7.41 m/s

Explanation:

Here momentum is conserved.

A 2,000-kg car moving east at 10.0 m/s collides with a 3,000-kg car moving north.

Initial momentum = 2000 x  10 i + 3000 x v j = 20000 i + 3000 v j

The cars stick together and move as a unit after the collision, at an angle of 48.0° north of east and at a speed of 5.98 m/s.

Mass = 2000 + 3000 = 5000 kg

Velocity = 5.98 cos 48 i + 5.98 sin 48 j = 4 i + 4.44 j

Final momentum = 5000 x (4 i + 4.44 j) = 20000 i + 22220 j

We have momentum is conserved

       20000 i + 3000 v j = 20000 i + 22220 j  

       3000 v = 22220

        v = 7.41 m/s

 Speed of the 3,000-kg car before the collision = 7.41 m/s

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

wavelength divides in half and speed stays the same.