Awater pipe is inclined 40.0° below the horizontal. the radius of the pipe at the upper end is 2.00 cm. if the gauge pressure at a point at the upper end is 0.112 atm, what is the gauge pressure at a point 2.65 m downstream, where the pipe has narrowed to a 1.00 cm radius? the flow rate is 20.0? cm^3/s

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

at the upper end the area is given as

Also at the other end

now the speed at two ends is given as

now by Bernoulli's theorem we have

now we have

Now we have

prolly a beacuse the momentuem the car has increases while going down hill

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s