Agray kangaroo can bound across level ground with each jump carrying it 9.6 m from the takeoff point. typically the kangaroo leaves the ground at a 28º angle. if this is so: part a) what is its takeoff speed? express your answer to two significant figures and include the appropriate units. part b) what is its maximum height above the ground? express your answer to two significant figures and include the appropriate units

(A) 11 m/s

(B) 1.3 m

Explanation:

Horizontal range, R = 9.6 m

Angle of projection, theta = 28 degree

(A)

Use the formula of horizontal range

R = u^2 Sin 2 theta / g

u^2 = R g / Sin 2 theta

u^2 = 9.6 × 9.8 / Sin ( 2 × 28)

u = 10.65 m/s

u = 11 m/s

(B)

Use the formula for maximum height

H = u^2 Sin ^2 theta / 2g

H =

10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)

H = 1.275 m

H = 1 .3 m

we need to know the time interval during which the force acts. impulse of force = momentum change