An electron and a proton are each placed at rest in a uniform electric field of magnitude 554 n/c. calculate the speed of each particle 52.0 ns after being released. electron m/s proton m/s need ?

Explanation:

It is given that,

Electric field, E = 554 N/C

Time,

Electric force, F = qE

For both electron and proton,

For electron,

Using first equation of motion as :

u = 0

v = 5059600 m/s

or

v = 5.05 × 10⁶ m/s

For proton :

Using first equation of motion as :

u = 0

v = 2756 m/s

Hence, this is the required solution.

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