An airplane starts its takeoff by moving at 1.7 m/s. the plane must then accelerate at 3.0 m/s2 for the next 30s to reach its final takeoff speed. to the nearest tenth of a kilometer, how far does the plane travel while accelerating to its takeoff speed?

The distance is 1.4 km.

Explanation:

Given that,

Initial velocity u= 1.7 m/s

Accelerate a= 3.0 m/s²

Time = 30 s

We need to calculate the distance

Using equation of motion

Where, u = initial velocity

a = acceleration

t = time

Put the value in the equation

Hence, The distance is 1.4 km.

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