Fresh water flows through a horizontal tapered pipe. at the wide end its speed is 8 m/s. the difference in pressure between the two ends is 5338 pa. what is the speed (in m/s) of the water at the narrow end? round your answer to the nearest tenth.

8.64 m/s

Explanation:

v1 = 8 m/s, v2 = ?, P2 - P1 = 5338 Pa, density of water, d = 1000 kg/m^3

By the use of Bernoulli's theorem

P 1 + 1/2 x d x v1^2 = P2 + 1/2 x d x v2^2

P2 - P1 = 1/2 x d x (v2^2 - v1^2)

5338 = 0.5 x 1000 x (v2^2 - 64)

10.676 = v2^2 - 64

v2^2 = 74.676

v2 = 8.64 m/s  

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