would the numerical values of the thermal coefficients of linear expansion have been the same if the temperatures had been measured in degrees fahrenheit? explain, and give an example. 3. for a contraction with a negative fractional change, would the coefficient of thermal expansion be negative? explain. 4. when a mercury-in-glass thermometer is placed in hot water, the thermometer reading first drops slightly and then rises. explain why

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Answer it orbits high above earth to gain clearer images of light, it magnifies images relative to the human eye, it records most of the universe as it was in the past, not as it is now;

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