A4.00-kg object traveling 20.0 m/s west collides with a 6.00-kg mass object traveling 12.0 m/s east. the collision is perfectly elastic, what is the velocity of the 4.00-kg object after the collision?

The velocity of the 4.00 kg object after the collision is 12 m/s.

Explanation:

Given that,

Mass of object

Velocity of object

Mass of another object

Velocity of another object

We need to calculate the relative velocity

The relative velocity is 8 m/s in west before collision.

We know that,

In one dimensional elastic collision, the relative velocity before collision equals after collision but with opposite sign.

So, The relative velocity after collision must be 8 m/s in east.

So, The object of 6.00 kg is going 20 m/s and the object of 4.00 kg is slows down to 12 m/s.

Hence, The velocity of the 4.00 kg object after the collision is 12 m/s.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

an energy transformation flow diagram is shown

where is it ?