A20.0 kg box slides down a 12.0 m long incline at an angle of 30.0 degrees with the horizontal. a force of 50.0 n is applied to the box to try to pull it up the incline. the applied force makes an angle of 0.00 degrees to the incline. if the incline has a coefficient of kinetic friction of 0.100, then the increase in the kinetic energy of the box is: 300 j.
372 j.
410 j.
455 j.
525 j.

Explanation:

The forces on the box while it is sliding down are

1). Component of the weight along the inclined plane

2). Friction force opposite to the motion of the box

3). Applied force on the box

now we know that component of the weight along the inclined plane is given as

Now we know that other component of the weight of object is counterbalanced by the normal force due to inclined plane

now the kinetic friction force on the box is given as

now the Net force on the box which is sliding down is given as

now the work done by net force = change in kinetic energy of the box

trig 15.3 cos

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong