Be sure to answer all parts. calculate the mass of each of the following: (a) a sphere of gold with a radius of 12.5 cm. (the volume of a sphere with a radius r is v = (4/3)πr3; the density of gold is 19.3 g/cm3.) × 10 genter your answer in scientific notation. (b) a cube of platinum of edge length 0.049 mm (density = 21.4 g/cm3). × 10 genter your answer in scientific notation. (c) 67.1 ml of ethanol (density = 0.798 g/ml). g

(a)

The radius of the sphere is:

r = 12.5 cm

So the volume of the sphere of gold is

The density of gold is

So the mass of the sphere is

(b)

The length of one side of the cube is

L = 0.049 mm = 0.0049 cm

So the volume of the cube of platinum is

The density of platinum is

So the mass of the cube is

(c) 53.5 g

The volume of the ethanol is

V = 67.1 mL

While its density is

d = 0.798 g/mL

So the mass of the ethanol is

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

the answer is 12 as i may remember

: )