Ageiger tube is designed to detect radiation in a nuclear physics laboratory. this instrument consists of a metal cylindrical tube that has a metallic wire along its central axis. the diameter of the wire will be 0.500 mm and the internal diameter of the tube 4.00 cm. the tube is filled with a diluted gas that is ionized at the action of a certain electric field value between the conductors. suppose that the ionizing radiation produces a distance of 1.50 cm from the axis of the central wire of the counter. assume that the center wire is positively charged and has a linear load density equal to 76.5 x 10-12 c/m. the metal tube is at a zero potential. 2.1. find an expression for the electric potential at a distance between the two conductors. from this expression, calculate the electrical potential that you experience in your initial position. 2.2 is the work done by the electric force on the means to carry from its initial position to the wire? 2.3 what will be the speed of the electron when it hits the wire? (me 9,11x10-31 kg)

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50 meters per 5 seconds

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Answer59.2kg; /