Two particles of mass m each are connected by q15 a mass less spring of length / and spring constant k. the system is lying (in the relaxed state) on a frictionless horizontal table, a very short impulse p is applied to the first mass (along the axis of the system) at t = 0. when would the second mass first come to rest? 2m (b) t = 27t. k 2m (a) t = t m (c) t t 2k m (d) t t, k

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You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero. 

I'm pretty sure the answer is c