The earth’s atmosphere pushes down on the surface of the earth with a force of 14.7 lb for each square inch of the earth’s surface. what is the weight of the earth’s atmosphere? the radius of the earth is about 6373 km.

The answer is frictional force

Scissors and a seesaw both cut things that’s the only comparison

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j