Atow truck drags a stalled car along a road. the chain makes an angle of with the road and the tension in the chain is 1500 n. how much work is done by the truck in pulling the car 1 km?

work = 1,305kJ

Explanation:

angle= 30°

force= 1,500N

distance= 1,000m

The formula for work is : Work= force x distance, however there is an angle of 30° between the direction of force applied and the direction of motion, therefore force must be decomposed to its value on the horizontal axis which is the direction of motion by using the cosine of the very angle.

W= F×cos(α)×D

W= 1,500×cos (30)×1,000

W= 1,305kJ ( kilojoules)

a=d/t

a="triangle"v/t

explanation:

a = acceleration

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