Acylindrical resistor has a length of 2 m and a diameter of 0.1 m. if i hook up a 12 v battery to the resistor and notice that the current flowing through the resistor is 3.2 a, what is the resistivity of the resistor? a. 4.12 x 103 ? m b. 1.15 x 103 ? m c. 6.10 x 102 ? m d. 1.47 x 102 m

 D . 1.47 x 10⁻² Ω-m

Explanation:

L = length of the cylindrical resistor = 2 m

d = diameter = 0.1 m

A = Area of cross-section of the resistor = (0.25) d² = (0.25) (3.14) (0.1)² = 0.785 x 10⁻² m²

V = battery Voltage = 12 volts

= current flowing through the resistor = 3.2 A

R = resistance of the resistor

Resistance of the resistor is given as

R = 3.75 Ω

= resistivity

Resistance is also given as

=  1.47 x 10⁻² Ω-m

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach