Determine the automobile’s braking distance from 90 km/h when it is going up a 5° incline. (round the final value to one decimal place.) the automobile’s braking distance from 90 km/h when it is going up a 5° incline is:

366 m

Explanation:

u = 90 km/h = 25 m/s,

theta = 5 degree

acceleration, a = g Sin theta = 9.8 x Sin 5 = 0.854 m/s^2

The final velocity os zero and let the braking distance be s.

Use third equation of motion

v^2 = u^2 - 2 a s

0 = 25 x 25 - 2 x 0.854 x s

s = 366 m

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