Aprojectile is fired into the air at a nonzero angle with the horizontal. when the projectile reaches its maximum height, the speed of the projectile is 50.8% of its original speed. what angle was the projectile originally fired at?

59.5 deg

Explanation:

= original speed at which the projectile is launched

θ = angle of launch of projectile

= component of speed along the horizontal direction =   Cosθ

At the highest position, the vertical component of velocity becomes zero and there is only horizontal component of velocity, hence

= velocity at the highest point = = Cosθ

it is given that

= 0.508

so

Cosθ = 0.508

Cosθ = 0.508

θ = 59.5 deg

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