Aprojectile is launched with initial speed v and angle ? over level ground. the projectile's maximum height h and horizontal range d are related by the equation d = 1.8h, what was the launch angle of the projectile?

65.75 deg

Explanation:

v = initial speed of launch of projectile

θ = initial angle of launch

H = maximum height of the projectile

maximum height of the projectile is given as

        eq-1

D = horizontal range of the projectile

horizontal range of the projectile is given as

                    eq-2

It is also given that

D = 1.8 H

using eq-1 and eq-2

tanθ = 2.22

θ = 65.75 deg

a coal burning power plant

0.11 m/s and 0.28 m/s should be correct