Physics, 12.07.2019 23:20 jeremytheprimerapper

A0.350 kg iron horseshoe that is initially at 600°c is dropped into a bucket containing 21.9 kg of water at 21.8°c. what is the final equilibrium temperature (in °c)? neglect any heat transfer to or from the surroundings. do not enter units.

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Answer from: puchie1225

22.8^0C

Explanation:-

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$

where,

m_1 = mass of iron horseshoe = 0.35 kg = 350 g (1kg=1000g[/tex]

m_2 = mass of water = 21.9 kg = 21900 g

$T_{final}$ = final temperature = ?

T_1 = temperature of iron horseshoe = 600^oC

T_2 = temperature of water = 21.8^oC

c_1 = specific heat of iron horseshoe = 0.450J/g^0C

c_2 = specific heat of water = 4.184J/g^0C

Now put all the given values in equation (1), we get

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$

$350\times 0.450\times (T_{final}-600)^0C=-[21900g\times 4.184\times (T_{final}-21.8)]$

$T_{final}=22.8^0C$

Therefore, the final equilibrium temperature is 22.8^0C .

Answer from: Quest

Julia would be observing a. static electricity was caused by her sweater rubbing against her shirt and transferring electrons. she didn't touch anything metal, so that would cancel out b.she most likely didn't rub her sweater against her hair either, so that cancels out c.she also didn't scoot across the carpet while trying to take her sweater off, that cancels out d.so that leaves a.a. is correct.

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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