Calculate the rate of heat transfer by radiation from a car radiator at 111 °c into a 45 °c environment, if the radiator has an emissivity of 0.75 and a 1.6 m^2 surface area.

783.63 Watt

Explanation:

T = 111 degree C = 111 + 273 = 384 K

T0 = 45 degree C = 45 + 273 = 318 K

A = 1.6 m^2

e = 0.75

According to the Stefan's law, the energy radiated per second is given by

E = 783.63 Watt

answer: he got 23

explanation:

ill do it for 100, also this isnt 80 its 40