The position of an electron is measured within an uncertainty of 0.100 nm. what will be its minimum position uncertainty 2.00 s later? {3.32 x 106 m}

Minimum uncertainty in position is

Explanation:

It is given that,

Uncertainty in the position of an electron,

According to uncertainty principle,

Let is the uncertainty in position after 2 seconds such that,

or

Hence, this is the required solution.

the answer for apex is the lowest

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft