To move a 51kg cabinet across a floor requires a force of 200n to start it moving, but then only 100n to keep it moving a steady speed. (a) find the maximum coefficient of static friction between the cabinet and the floor. (b) find the coefficient of kinetic friction between the cabinet and the floor.

a)

b)

Explanation:

Given:

Mass of the cabinet, m = 51 kg

a) Applied force = 200 N

Now the force required to move the from the state of rest (F) = coefficient of static friction ()× Normal reaction(N)

N = mg

where, g = acceleration due to gravity

⇒N = 51 kg × 9.8 m/s²

⇒N = 499.8 N

thus, 200N  = × 499.8 N

⇒ =

b) Applied force = 100 N

since the cabinet is moving, thus the coefficient of kinetic() friction will come into action

Now the force required to move the from the state of rest (F) = coefficient of kinetic friction ()× Normal reaction(N)

N = mg

where, g = acceleration due to gravity

⇒N = 51 kg × 9.8 m/s²

⇒N = 499.8 N

thus, 100N  = × 499.8 N

⇒ =

f=gm1m2/d^2 it d

f is force g is gravitaiton constant, m1 is mass of first object, m2 is mass of second object. d is distance between two object

c

explanation: