Two resistors, the first 12 ? and the second 6 2, are connected in parallel to a 48 v battery what is the power dissipated by each resistor? a) p1 144 w, p2-288 w b) p1-162 w, p2-324 w c) p1-180 w, p2-360 w d) p1-192 w, p2 384 w

P₁ = 192 W and P₂ = 384 W

Explanation:

It is given that,

Resistor 1,

Resistor 2,

Voltage, V = 48 V

Power dissipated by resistor 1 is given by :

P₁ = 192 watts

Power dissipated by resistor 2 is given by :

P₂ = 384 watts

So, the power dissipated by both the resistors is 192 watts and 384 watts respectively. Hence, this is the required solution.

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.