Multiple-concept example 7 discusses how problems like this one can be solved. a 6.00-μc charge is moving with a speed of 8.70 x 104 m/s parallel to a very long, straight wire. the wire is 6.30 cm from the charge and carries a current of 86.0 a. find the magnitude of the force on the charge.

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).

Crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied

The slope of a velocity time graph over any interval of time gives the during that interval