In a hurricane, air moves along the ocean surface into the eye of the hurricane. at the eyewall the temperature is still t2=303k but the pressure has dropped to p2=0.900bars . in addition, near the eyewall the air becomes saturated with water, and each kilogram of air contains about 28 grams of liquid water. this water evaporates when heat is adsorbed from the ocean at t2=303k. calculate δs2, the entropy change in moving 1.00 kilogram of air from the reference state to the eyewall. include both the entropy increase from the pressure change of the air and from the water evaporation. assume for water at t=303k δhvap=45.0kjmol−1 .

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russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.