Physics, 17.07.2019 20:20 flex23

Abartender slides a beer mug at 1.6 m/s towards a customer at the end of a frictionless bar that is 1.1 m tall. the customer makes a grab for the mug and misses, and the mug sails off the end of the bar.
(a) how far away from the end of the bar does the mug hit the floor?
m
(b) what are the speed and direction of the mug at impact?
speed m/s
direction ° below the horizontal

Answers: 3

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Answers

Answer from: Bhoom1871

(a): the mug hits the floor 0.752m away from the end of the bar.

(b): the speed of the mug at impact are:

V= 4.87 m/s

direction= 70.82º below the horizontal.

Explanation:

Vx= 1.6 m/s

Vy=?

h= 1.1 m

g= 9.8 m/s²

t is the fall time

$t=\sqrt{\frac{2*h}{g} }$

t=0.47 sec

Vy= g*t

Vy= 4.6 m/s

$V=\sqrt{Vx^{2} +Vy^{2}$

V= 4.87 m/s

α= tan⁻¹(Vy/Vx)

α= -70.82º

Answer from: jess7kids

(a) x = 0.758 m

(b) v = 4.9 m/s, α = 70.97° below the horizontal

Explanation:

The movement is semi-parabolic because the initial velocity is horizontal.

The equations of semiparabolic motion are:

x movement : uniform line movement

x= vx*t Equation (1)

Where:

x: horizontal position in meters (m)

t : time (s)

vx: horizontal velocity in m/s

y movement: free fall motion

y = (1/2)g*t² Equation (2)

vy= g*t Equation (3)

Where:

y: vertical position in meters (m)

t : time in seconds (s)

vy: vertical velocity in m/s

g: acceleration due to gravity in m/s²

Data

Vx = 1.6 m/s

y = 1.1 m

g = 9.8 m/s²

Time it takes for the beer mug to hit the floor

We replace in the formula (2)

y = (1/2)g*t²

1.1 = (1/2) (9.8)*t²

t² =(2*1.1)/ (9.8)

$t = \sqrt{\frac{2*1.1}{9.8} }$

t= 0.474 s

Horizontal distance the mug reaches

We replace vx= 1.6 m/s and t= 0.474 s in the formula (1):

x = vx*t = (1.6) *(0.474)

x = 0.758 m

Speed (v) and direction (α) of the mug at impact :

In the Equation (3): vy= g*t = 9.8* 0.474 = 4.645 m/s (downward)

$v = \sqrt{v_{x}^{2}+v_{y}^{2} }$

$v = \sqrt{1.6^{2}+4.645^{2} }$

v = 4.9 m/s

$\alpha = tan^{-1} (\frac{v_{y} }{v_{x} } )$

$\alpha = tan^{-1} (\frac{-4.645 }{1.6} )$

α = - 70.97°

α = below the horizontal

Answer from: Quest

it was given as a lesson and guide for prayer.

Answer from: Quest

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf, ℰ, to a battery's terminal voltage, v, current, i, and internal resistance, r, is ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

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Abartender slides a beer mug at 1.6 m/s towards a customer at the end of a frictionless bar that is...