Two 10-cm-diameter charged rings face each other, 25.0 cm apart. both rings are charged too + 50.0 nc . what is the electric field strength?

6773.54 V/m

Explanation:

Given data

Distance between two rings(x)=25cm

Charge on each ring(Q)= C

diameter of ring(d)=10 cm

Now Electric field strength at distance x from ring=

Where K=coulomb's constant==8.98\times 10^{9]

Now electric field strength at midpoint between two rings is zero

because one is pointing towards positive x direction and other in negative z direction.

but electric field strength at center of ring  due to other ring is given by

=

=

=6773.54 V/m

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min