Adentist's drill starts from rest. after 3.00 s of constant angular acceleration it turns at a rate of 2.60 x 104 rev/min (a) find the drill's angular acceleration. rad/s (b) determine the angle (in radians) through which the drill rotates during this period rad

(a)

907.11 rad/s²

(b)

4082 rad

Explanation:

(a)

t = time taken = 3.00 s

w₀ = initial angular velocity of the drill = 0 rad/s

w = final angular velocity of the drill = 26000 rev/min = 26000 = 2721.33 rad/s

α = angular acceleration of the drill

t = time interval = 3.00 s

using the equation

w = w₀ + α t

2721.33 = 0 + α (3)

α = 907.11 rad/s²

(b)

θ = angle

using the equation

θ = w₀ t + (0.5) α t²

θ = (0) (3.00) + (0.5) (907.11) (3.00)²

θ = 4082 rad

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

answer: 31, 5556. 952 seconds