At noon, ship a is 50 nautical miles due west of ship b. ship a is sailing west at 22 knots and ship b is sailing north at 23 knots. how fast (in knots) is the distance between the ships changing at 3 pm? (note: 1 knot is a speed of 1 nautical mile per hour.)

30.66 knots

Explanation:

Distance of ship A from B at noon = 50 NM

= Velocity of ship A = 22 knots = 22 NM/h

= Velocity of ship B = 23 knots = 23 NM/h

Distance travelled by ship A from noon to 3 PM = 22×3 = 66 NM

a = Total distance travelled by ship A = 50+66 = 116 NM

b = Total distance travelled by ship B till 3 PM = 23×3 = 69 NM

c = Distance between Ship A and B at 3 PM = √(116²+69²) = 134.97 NM

a²+b² = c²            (Pythagoras theorem)

Now differentiating with respect to time

∴ The velocity with which the distance is changing at 3 PM (3 hours later) is 30.66 knots

see earlier

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