What accelerating potential is needed to produce electrons of wavelength 5.20 nm? v- 10.5563 previous answers reguest answer submit incorrect; try again; 5 attempts remaining ▼ part b what would be the energy of photons having the same wavelength as these electrons? ev submit request answer

(a) 55.67 mV

(b) 238 eV

Explanation:

(a) Let the accelerating voltage is v.

The formula for the accelerating voltage and the potential difference is given by

Here, λ = 5.20 nm = 5.20 x 10^-9 m

V = 0.0556 V = 55.67 mV

(b) Let the energy is E.

The formula for the energy is given by

E = (6.6 x 10^-34 x 3 x 10^8) / (5.2 x 10^-9) = 3.8 x 10^-17 J

E = (3.8 x 10^-17) / (1.6 x 10^-19) = 238 eV

the answer is b

explanation:

whichever one it is, it's definitely not one that you included on the list you provided.