Light with a wavelength of 310 nm is incident on a metal that has a work function of 3.8 ev. what is the maximum kinetic energy that a photoelectron ejected in this process can have?

3.32×10⁻²⁰ J

Explanation:

Given :

Wavelength of the light λ = 310 nm

work function, W₀ = 3.8 eV

The maximum kinetic energy () is given as:

Where,

h = Planck's constant (6.626 × 10⁻³⁴ Js)

c = speed of light (3 × 10⁸)

also, 1 eV = 1.6 × 10⁻¹⁹ J

substituting the values in the above equation we get

i think they are all correct

explanation:

they seem good

0.11 m/s and 0.28 m/s should be correct