Anonpipelined system takes 200ns to process a task. the same task can be processed in a 5-segment pipeline with a clock cycle of 40ns. determine the speedup ratio of the pipeline for 200 tasks. what is the maximum speedup that could be achieved with the pipeline unit over the nonpipelined unit?

Given:

Time taken by non pipelined system = 200 ns = 200 s

Clock cycle for 5- segment pipeline = 40 ns = 40 s

Pipeline speed up ratio = 200

Formula used:

Solution:

Using formula:

= 5

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.