Gibbons, small asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. a 9.0 kg gibbon has an arm length (hand to shoulder) of 0.60 m. we can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. at the lowest point of its swing, the gibbon is moving at 3.2 m/s .
what upward force must a branch provide to support the swinging gibbon?
express your answer to two significant figures and include the appropriate units.
(textbook is college physics by: knight, jones, and field.)

2.4 x 10² N

Explanation:

= mass of the gibbon = 9.0 kg

= arm length of the gibbon = 0.60 m

= speed of gibbon at the lowest point of swing = 3.2 m/s

 = weight of the gibbon in downward direction

= Upward force provided by the branch

weight of the gibbon in downward direction is given as

= g

 = (9.0) (9.8)

 = 88.2 N

Force equation for the motion of gibbon at the lowest point is given as

= 241.8 N

= 2.4 x 10² N

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

6 cos 34, 6 sin 34 trig