Aball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of the building. ignore air resistance. how long is the ball in the air?

3.50 s

Explanation:

The movement of the ball has a vertical component and a horizontal component. The vertical movement is can be represented through a Uniformly Accelerated Motion (constant acceleration), while the horizontal movement can be represented through a Uniform Motion (constant speed).

We can find the time (t) that the ball was in the air just by considering the vertical movement. The initial vertical speed (v₀) is 0 (the ball is thrown horizontally), the vertical distance traveled (y) is 60.0 m, and the acceleration (a) is that of gravity. Then.

y = 1/2 × a × t²

t = √(2 × y/ a) = √(2 × 60.0 m/ 9.81 m/s²) = 3.50 s

the largest known star in the universe is uy scuti, a hypergiant with a radius around 1,700 times larger than the

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day