(a) at an air show a jet flies directly toward the stands at a speed of 1200 km/h, emitting a frequency of 3500 hz, on a day when the speed of sound is 342 m/s. what frequency is received by the observers? (b) what frequency do they receive as the plane flies directly away from them?

a) 1.4 x 10⁵ Hz

b) 1.8 x 10³ Hz

Explanation:

a)

= speed of sound = 342 m/s

= speed of jet = 1200 km/h = 333.33 m/s

= actual frequency = 3500 Hz

= observed frequency

Observed frequency is given as

= 1.4 x 10⁵ Hz

b)

= speed of sound = 342 m/s

= speed of jet = 1200 km/h = 333.33 m/s

= actual frequency = 3500 Hz

= observed frequency

Observed frequency is given as

= 1.8 x 10³ Hz

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//