A1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. the automobile's center of mass is on the centerline at a point 1.15 m behind the front axle. find the force exerted by the ground on each wheel.

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

now from above equation

now we have

now the other force is given as

the independent variable, or the one that is intentionally manipulated is the speed.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow