Now, using ohm's law:
i=vr and the total resistance calculated in #3, what is the total current of this circuit?
• 0.15 a
• 0.30 a
• 0.45 a
• 0.60 a
drag the voltmeter from the toolbox on the right. a voltmeter measures the difference in the voltage between 2 places on a circuit. this is called the voltage drop. place the contacts of the voltmeter on the circuit on either side of the battery (pictured below).
what is the voltage drop across the battery?
• -1.00 v
• -3.00 v
• -9.00 v
• -12.00 v
place the contacts on either side of the 10 ohm resistor.
what is voltage drop across the 10 ohm resistor?
• -3.00 v
• -4.50 v
• -6.00 v
• -9.00 v
what is the voltage drop across the 20 ohm resistor?
• -3.00 v
• -4.50 v
• -6.00 v
• -9.00 v
add together your answers from #6 and #7. is this number greater than, less than, or equal to the voltage of our battery?
• greater than
• less than
• equal to
change the voltage of the battery from 9 v to 15 v by ctrl-clicking on the battery and selecting “change voltage”.
use the voltmeter to remeasure the voltage across each of the resistors. now how does the total voltage across the resistors compare to that of the battery?
• greater than
• less than
• equal to
change the battery’s voltage back to 9 volts, use three more wires. is this circuit arranged in series, in parallel, or in both formations?
• series
• parallel
• both series and parallel