A50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. if your car's cooling system holds 4.40 gallons, what is the boiling point of the solution?
make the following assumptions in your calculation: at normal filling conditions, the densities of engine coolant and water are 1.11 g/ml and 0.998 g/ml respectively. assume that the engine coolant is pure ethylene glycol (hoch2ch2oh), which is non-ionizing and non-volatile, and that the pressure remains constant at 1.00 atm. also, you'll need to look up the boiling-point elevation constant for water.

109.09°C

Explanation:

Given data:

The capacity of the car cooling system =  4.40 gallons

Ratio of water and solute = 50/50

thus,

Volume of solute = Volume of water = 4.40/ 2 gallons = 2.20 gallons

thus, the Mass of solute, M₁ = Density × Volume = 1.1 g/mL × = 9160.69 grams

Mass of water = 0.998 g/mL × = 8310.346 grams

molality , m =

on substituting the values, we get

m = =  17.759 m

Now, the elevation in boiling point is given as:

where,

is a constant = 0.512 °C/m

on substituting the values we get

Boiling point = 100°C + 17.759 × 0.512= 109.09°C

The boiling point of the solution will be equal to 109.09°C.

We can arrive at this answer as follows:

First, we must take into account that the water and solute ratio is 50/50, therefore, we must divide the capacity of the car's cooling system by 2, to know the volume of solute and solvent, which will be equal per account of the reason between them.

gallons

We must take into account that is a constant and its value is always 0.512 °C/m.

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well clustered together.

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0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

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