Two forces of magnitude 20n each are acting at 30 and 60 degree with xaxis the y component of the resultant force is

We can find the y-component of the resultant force by adding the y-components of the two 20N forces.

For a force of magnitude F and lying at an angle off the x-axis θ, the y-component of the force is given by:

Fsin(θ)

The magnitude of the two forces is 20N, and they lie at 30° and 60°, so the sum of their y-components, and therefore the y-component of the resultant force, is:

20sin(30°)+20sin(60°)

= 27.3N

e) none of the above answers are correct

the answer is b

explanation: