A6.0 ω and a 12. ω resistor are connected in series to a 36. v battery, what power is dissipated by the 12.0 ω resistor? a) 24. w b) 486. w c)216. w d) 12. w e) 48. w

Is dissipated E) P= 48 W in the 12 Ω resistor.

Explanation:

V= 36v

Req= (12 + 6)Ω

Req= 18Ω

I = V/ Req

I= 2 A

P= I² * R(12Ω)

P= 48 W

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get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.