Physics, 27.07.2019 00:10 legendman27

Use gauss' law to obtain the electric field of an infinite sheet of charge with uniform charge density ps. take the sheet as lying in the xy plane of the cartesian coordinate system.

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Draw a cylinder with height H and having circular faces each with area A such that the infinite sheet is parallel to the cylinder's circular faces and the sheet cuts the cylinder in half.

Because the sheet is infinitely large and lies in the x-y plane, the electric field only points in the +z or -z direction.

Calculate the electric flux through the cylinder. The cylinder's body runs parallel to the electric field while its circular faces are perpendicular to the field, so there is only electric flux through the cylinder's circular faces. The electric field E is the same along the circular faces, so the flux through one circular face is equal to EA. Therefore the total electric flux through the cylinder is Φ = 2EA.

Remember that the electric flux is proportional to the enclosed charge:

Φ = Q_{enclosed}/ε₀

The cylinder encloses a portion of the sheet having an area equal to one of its circular faces, A. Therefore the cylinder encloses an amount of charge given by:

Q_{enclosed} = σA

Now we have:

2EA = σA/ε₀

Solve for E:

E = σ/(2ε₀)

Answer from: Quest

answer: cesare beccaria developed the classical school of criminology with from philosopher jeremy bentham

explanation:

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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