Two out of phase loudspeakers are some distance apart. a person stands 4.50 m from one speaker and 3.80 m from the other. what is the third lowest frequency at which the person will hear constructive interference? the speed of sound in air is 347 m/s. hz

The third lowest frequency is 1489.27 Hz.

Explanation:

Given that,

Distance of person from one speaker= 4.50 m

Distance of person from the other = 3.80 m

The longest wavelength is the shortest frequency.

We need to calculate the difference between the speakers

The difference between the speakers d= 4.50-3.80 =0.7 m

We know that,

The longest wavelength is such that one wavelength

So, The third longest wavelength is

Put the value of d

We need to calculate the lowest frequency

Using formula of frequency

Hence, The third lowest frequency is 1489.27 Hz.

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