A7.5-kg otter slides down a hill, starting from rest at the top. the sloping surface of the hill is 8.8 m long, and the top is 6.5 m above the base. g no friction, what should the otter's speed be at the bottom? b. if the speed of the otter at the bottom of the hil is 9.2 m/s, how much energy was lost to nonconservative forces on the hill?

Part a)

v = 11.3 m/s

Part b)

Energy loss = 160.8 J

Explanation:

Part a)

By Energy conservation we can say that the total energy of the otter at the top of the hill must be same as the total energy of the otter at the bottom of the hill

So we will have

here we know that

H = 6.5 m

now we have

Part b)

If there is no energy loss then the final speed of the otter at the bottom is given as 11.3 m/s

so final kinetic energy is

while if it has some conservative force then the final speed will be 9.2 m/s

so final kinetic energy will be

now the energy loss is given as

this means that the temperature of both substances will be equal

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.