On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 n/c. compare the gravitational and electric forces on a small dust particle of mass 1.5 ✕ 10−15 g that carries a single electron charge.

If an object is moving or in motion

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.